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-7x^2-5x+3=0
a = -7; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·(-7)·3
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{109}}{2*-7}=\frac{5-\sqrt{109}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{109}}{2*-7}=\frac{5+\sqrt{109}}{-14} $
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